The Sum Of Two Numbers Is 40 And Their Difference Is 8
The problem given says that 2 unknown numbers are given, whose sum is equal to 40 and the difference is 8. Let's find the two numbers :When we add the two numbers :
X + Y = 40
The difference of two numbers :
X - Y = 8
Solution :
If we add the two equations eachother , then we can find the first number.
X + Y = 40 X - Y = 8 2X = 48 |
Let's divide 48 to 2 for the first number "X" .
X/2 = 24
First number is 24
X + Y = 40
So ;
24 + Y = 40
Y = 40 - 24
Y = 16
Second number is 16
Question & Answer
The Sum Of Two Numbers Is 40 And Their Difference Is 8 : 24 And 16