The Sum Of Two Numbers Is 41 And Their Difference Is 7

The problem given says that 2 unknown numbers are given, whose sum is equal to 41 and the difference is 7. Let's find the two numbers :

When we add the two numbers :
X + Y = 41

The difference of two numbers :
X - Y = 7

Solution :

If we add the two equations eachother , then we can find the first number.

X + Y = 41
X - Y = 7

2X = 48

Let's divide 48 to 2 for the first number "X" .

X/2 = 24

First number is 24

X + Y = 41
So ;
24 + Y = 41
Y = 41 - 24
Y = 17

Second number is 17

Question & Answer
The Sum Of Two Numbers Is 41 And Their Difference Is 7 : 24 And 17

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