The Sum Of Two Numbers Is 41 And Their Difference Is 8

The problem given says that 2 unknown numbers are given, whose sum is equal to 41 and the difference is 8. Let's find the two numbers :

When we add the two numbers :
X + Y = 41

The difference of two numbers :
X - Y = 8

Solution :

If we add the two equations eachother , then we can find the first number.

X + Y = 41
X - Y = 8

2X = 49

Let's divide 49 to 2 for the first number "X" .

X/2 = 24.5

First number is 24.5

X + Y = 41
So ;
24.5 + Y = 41
Y = 41 - 24.5
Y = 16.5

Second number is 16.5

Question & Answer
The Sum Of Two Numbers Is 41 And Their Difference Is 8 : 24.5 And 16.5

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